88=2w^2

Solution for 88=2w^2 equation:

88=2w^2

We move all terms to the left:

88-(2w^2)=0

a = -2; b = 0; c = +88;
Δ = b2-4ac
Δ = 02-4·(-2)·88
Δ = 704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{704}=\sqrt{64*11}=\sqrt{64}*\sqrt{11}=8\sqrt{11}$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{11}}{2*-2}=\frac{0-8\sqrt{11}}{-4}
=-\frac{8\sqrt{11}}{-4}
=-\frac{2\sqrt{11}}{-1}
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{11}}{2*-2}=\frac{0+8\sqrt{11}}{-4}
=\frac{8\sqrt{11}}{-4}
=\frac{2\sqrt{11}}{-1}
$